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Computes 2D Periodogramm. Consider the discrete Fourier transform of the sample: $$J({\omega}) = \frac{1}{\sqrt{2\pi NM}} \sum_{s\in S} x(s)\,\exp\!\left(-i\langle s,{\omega}\rangle\right)$$

Then the 2D periodogram is given by: $$I(\omega_{kl}) = J(\omega_{kl})\,\overline{J(\omega_{kl})} = \big|J(\omega_{kl})\big|^2$$

Usage

I(x)

Arguments

x

Matrix with data from stationary spatial process

Value

Numeric matrix with N rows and M cols

Examples

x <- gridMA(25, 25, MA_coef_all(.7))
image(I(x))